Question

Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is :

• A. 30.2 MeV
• B. 32.4 MeV
• C. 23.6 MeV
• D. 25. 8 MeV

Answer 1

The correct option is C 23.6 MeV

Solution: The binding energy per nucleon for deuteron is equal to 1.1 MeV and for helium is equal to 7.0 MeV.

As we know,

$H_1^2+H_1^2\to H{e}_2^4$

So, total binding energy for two deuterium nuclei is given by,

$1.1\times 4=4.4MeV$

Also, binding energy of $H{e}_2^4$ nuclei is given by,

$4\times 7=28MeV$

Therefore final energy released in the process = 28-4.4 = 23.6 MeV

Hence, the correct option is (C).