Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take g= 10 $m / s^{2} .$

Open in App

Solution

$W h e n t h e s e c o n d d i a m o n d i s d r o p p e d, t h e s p e e d o f t h e s e c o n d d i a m o n d i s v = u - g t = 0 - 1 = - 10 m / s t h u s, t h e r e l a t i v e v e l o c i t y o f t h e t w o d i a m o n d s i s 10 m / s . A f t e r 1 s e c (a t t h e t i m e w h e n s e c o n d d i a m o n d i s d r o p p e d), d i s p l a c e m e n t o f t h e f i r s t d i a m o n d i s \frac{1}{2} g t^{2} = 5 m t h u s, t i m e f o r t h e d i s t a n c e b e t w e e n t h e m t o b e 10 m i s 1 s + \frac{5}{10} s = 1.5 s$

Suggest Corrections

Similar questions

Q. Two bodies start falling freely from the rest from the same height at an interval of 1 s. How long after the first body begins to fall will the two bodies be 10 m apart? (g = 10

m / s^{2}

)

Two particles are released from the same height at an interval of 1 second how long after the first particle begins to fall will the two partocles be 10 m apart

Two particles are released from the same height at an interval of 1sec.How long after the first particle begin to fall ,will the two particles be 10m apart ?

Q. Two bodies begin a free fall from the same height at a time interval of

N

s. If vertical separation between the two bodies is

1

m after

n

seconds from the start of the first body, then

n

is equal to:

Q. A body falling freely under gravity passes two points 30 m apart in 1s. From what point above the upper point it began to fall?(Take g = 9.8 m

s^{2}

Join BYJU'S Learning Program

Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take g= 10 m/s2.

Whentheseconddiamondisdropped,thespeedoftheseconddiamondisv=u−gt=0−1=−10m/sthus,therelativevelocityofthetwodiamondsis10m/s.After1sec(atthetimewhenseconddiamondisdropped),displacementofthefirstdiamondis12gt2=5mthus,timeforthedistancebetweenthemtobe10mis1s+510s=1.5s

Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take g= 10 $m / s^{2} .$