Two dice are placed side by side with $4 + 2$ , what is the total on the face opposite to the given numbers?

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Solution

Since, in any die, sum of the opposite face is always $7$ .
So,
Face opposite to $4 = 7 - 4 = 3$
Face opposite to $2 = 7 - 2 = 5$
Required sum = $3 + 5 = 8$
Hence, Option B is correct.

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Two dice are placed side by side with 4+2, what is the total on the face opposite to the given numbers?

Since, in any die, sum of the opposite face is always 7.So,Face opposite to 4=7−4=3Face opposite to 2=7−2=5Required sum = 3+5=8Hence, Option B is correct.

Two dice are placed side by side with $4 + 2$ , what is the total on the face opposite to the given numbers?

Since, in any die, sum of the opposite face is always $7$ .
So,
Face opposite to $4 = 7 - 4 = 3$
Face opposite to $2 = 7 - 2 = 5$
Required sum = $3 + 5 = 8$
Hence, Option B is correct.