Question

Two dice are rolled by two players A and B. A throws total 10, the probability that B throws more than A is ______.

• A. 1/12
• B. 1/36
• C. 1.18
• D. None of the above

Answer 1

The correct option is A 1/12

$total\text{no}\text{. of cases in a pair of dice=36}$
$\text{sum}\text{of 10 can be obtained in}(6,4)(4,6)(5,5)\text{=3way}$
$\text{sum}\text{of greater}than10canbeobtainedin(6,5)(5,6)(6,6)=3ways$
$ProbabilityofA=\frac{3}{36}=\frac{1}{12}$
$ProbabilityofB=\frac{3}{36}=\frac{1}{12}$