Question

Two dice are thrown at a time, find the probability that the sum obtained is less than $6$.

• A. $\frac{2}{9}$
• B. $\frac{1}{4}$
• C. $\frac{5}{18}$
• D. $\frac{1}{3}$

Answer 1

Answer: (C)

$\frac{5}{18}$

When two dice are thrown at a time then

Total no. of outcomes,n(S)=$6\times 6=36$

The favorable outcomes$=(1,1),(1,2),(1,3),\left(1.4\right),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)$

$\Rightarrow$The no. of favorable outcomes,n(E)=10

$\therefore Probability=\frac{n\left(E\right)}{n\left(S\right)}=\frac{10}{36}=\frac{5}{18}$