Two dice are thrown at a time .What is the probability that sum of the numbers appearing on them is an even number?

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1/2

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Solution

The correct option is B
1/2

Total number of possible outcomes = 6 x 6= 36.
Total number of favorable outcomes = (1,1),(1,3),(1,5),(2,2),(2,4),
(2,6),(3,1),(3,3),(3,6),(4,2),(4,4),(4,6),(5,1),(5,3),(5,5),(6,2),(6,4),(6,6)= 18
$P r o b a b i l i t y = \frac{T o t a l n u m b e r o f f a v o u r a b l e o u t c o m e s}{T o t a l n u m b e r o f o u t c o m e s} = \frac{18}{36} = \frac{1}{2}$

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