Question

Two dice are thrown at the same time. Find the probability of getting different values on both.

• A. $\frac{1}{36}$
• B. $\frac{1}{6}$
• C. $\frac{1}{2}$
• D. $\frac{5}{6}$

Answer 1

The correct option is D

$\frac{5}{6}$

Let E be the event of getting different values on both the dice.
The complementary event is getting the same value on both, for which there are 6 favourable outcomes: (1, 1), (2, 2), (3, 3), (4, 4), (5, 5) and (6, 6).
Thus, P (not E) = $\frac{1}{6}$
$\therefore$ P (E) = 1 - P (not E) = 1 - $\frac{1}{6}$= $\frac{5}{6}$