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Question

Two dice are thrown. Find the probability of getting.
(a) The sum of the numbers on their upper faces is at least 9.
(b) The sum of the numbers on their upper faces is 15.
(c) The number on the upper face of the second die is greater than the number on the upper face of the first die.

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Solution

Sum of number is atlesat 9 in cases (6,3),(5,4),(4,5),(3,6),(6,4),(5,5),(4,6),(5,6),(6,5),(6,6).

Total number of favorable outcomes=10

Total number of outcomes=36

Probability 1036 =518

Sum of number on upper face is 15 is not possible because maximum is 12

Hence, probability is 0.

Number number on the upper face of the second die is greater than the number on the upper face of the first die is possible in (1,2),(1,3),(1,4),(1,5),(1,6),(2,3),(2,4),(2,5),(2,6),(3,4),(3,5),(3,6),(4,5),(4,6),(5,6)

Total number of favorable outcomes=15

Total number of outcomes=36

Probability 1536 =512

801081_838103_ans_e8a2c56447ba4c9d8fb2ad0d19d03655.jfif

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