Question

Two dice are thrown. Find the probability of getting the sum of the numbers on their upper faces is multiple of $9$.

Answer 1

Favorable cases

(3,6) (6,3) (4,5) (5,4)

Sample space $=36$

Probability of getting sum of numbers on upper face as multiple of 9

$=\frac{Favorablecases}{Samplespace}$

$=\frac{4}{36}$

$=1/9$