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Complement of an Event

Two dice are ...

Question

Two dice are thrown. Find the probability of getting the sum of the numbers on their upper faces is at the most $3$

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Solution

Favorable case
(1,2) (2,1) (1,1)
Sample space $= 36$
P(getting sum of numbers on upper face at most 3)
$= \frac{F a v o r a b l e c a s e s}{S a m p l e s p a c e}$
$= \frac{3}{36} = 1 / 12$

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