Question

Two dice are thrown. Find the probability of the event that the product of numbers on their upper faces is $12$.

Answer 1

Let $E$ be the favorable event, then

$E=\left\{\right(2,6),(6,2),(4,3),(3,4\left)\right\}$

So $n\left(E\right)=4$

Also sample space $n\left(S\right)=6\times 6=36$

Hence required probability is $=\frac{n\left(E\right)}{n\left(S\right)}=\frac{4}{36}=\frac{1}{9}$