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Independent Events

Two dice are ...

Question

Two dice are thrown. Find the probability that the sum of the numbers coming up on them is $9$ . If it known that the number $5$ always occurs on the first dice.

P (E_{1} / E_{2}) = \frac{1}{3}

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P (E_{1} / E_{2}) = \frac{1}{6}

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P (E_{1} / E_{2}) = \frac{1}{9}

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P (E_{1} / E_{2}) = \frac{5}{36}

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Solution

The correct option is B $P (E_{1} / E_{2}) = \frac{1}{6}$
Dice 1 has number 5.
Dice 2 may get any number $\Rightarrow$ $n (S) = 6$
To make the sum as 9,the second dice should get number 4 only $\Rightarrow$ $n (E) = 1$

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Which of the following statements is true?

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Two dice are thrown. Find the probability that the sum of the numbers coming up on them is 9. If it known that the number 5 always occurs on the first dice.

The correct option is B P(E1/E2)=16Dice 1 has number 5.Dice 2 may get any number ⇒ n(S)=6 To make the sum as 9,the second dice should get number 4 only ⇒ n(E)=1

Two dice are thrown. Find the probability that the sum of the numbers coming up on them is $9$ . If it known that the number $5$ always occurs on the first dice.

The correct option is B $P (E_{1} / E_{2}) = \frac{1}{6}$
Dice 1 has number 5.
Dice 2 may get any number $\Rightarrow$ $n (S) = 6$
To make the sum as 9,the second dice should get number 4 only $\Rightarrow$ $n (E) = 1$