Two dice are thrown simultaneously. Find the probability of getting a multiple of 2 on first dice and a multiple of 3 on the second dice.
A
46
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
26
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
16
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
136
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B16 Total cases = 6×6 Let A be the event of getting a multiple of 2 on first dice and a multiple of 3 on the second dice. Hence, A={(2,3),(2,6),(4,3),(4,6),(6,3),(6,6)} n(A)=6 ∴P(A)=636=16 ∴ Option C is correct.