Question

Two dice are thrown simultaneously. Find the probability of getting a total of at least $10$.

• A. $\frac{5}{6}$
• B. $\frac{1}{6}$
• C. $\frac{1}{3}$
• D. None of these

Answer 1

The correct option is B $\frac{1}{6}$

Total number of possible cases $=36$
Favourable cases of getting a total of at least $10$
$=\left\{\right(4,6),(5,5),(5,6),(6,4),(6,5),(6,6\left)\right\}$
Total number of favourable cases $=6$
P(Total of at least $10$) = $\frac{6}{36}=\frac{1}{6}$