Question

Two dice are thrown simultaneously. The probability of getting a doublet is

• A. $0$
• B. $\frac{1}{3}$
• C. $\frac{1}{6}$
• D. $\frac{5}{6}$

Answer 1

The correct option is C

$\frac{1}{6}$

When the two dice are thrown simultaneously, all possible outcomes =$6^2$ = 36.
The favourable outcomes are: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)
Hence, the no. of favourable outcomes = 6
$\therefore$ P (getting a doublet) = $\frac{6}{36}=\frac{1}{6}$