Question

Two dice are thrown simultaneously. The probability of getting a doublet is:

[1 mark]

• A. $\frac{1}{6}$
• B. $\frac{2}{3}$
• C. $\frac{1}{3}$
• D. $\frac{1}{2}$

Answer 1

The correct option is A $\frac{1}{6}$

$\text{Total number of outcomes = 36}$
$\text{Favourable outcomes = (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), and (6, 6) = 6}$ $\text{Probability}=\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}=\frac{6}{36}=\frac{1}{6}$