Question

Two dice are thrown simultaneously. The probability of getting a pair of aces is
(a) $\frac{1}{36}$

(b) $\frac{1}{3}$

(c) $\frac{1}{6}$

(d) none of these

Answer 1

$$\begin{gathered} \left(\mathrm{a}\right)\frac{1}{36} \\ P\left(\text{pair of aces}\right)=P\left(\text{ace in first throw}\right)\times P\left(\text{ace in second throw}\right) \\ =\frac{1}{6}\times \frac{1}{6} \\ =\frac{1}{36} \end{gathered}$$