Question

Two dice are thrown simultaneously. The probability of getting a pair of aces is

• A. $\frac{1}{36}$
• B. $\frac{1}{3}$
• C. $\frac{1}{6}$
• D. none of these

Answer 1

The correct option is A

$\frac{1}{36}$

When two dice are thrown simultaneously, the sample space associated with the random experiment is given by :

$S=\left\{\right(1,1),(1,2),(1,3),.....(6,4),(6,5),(6,6\left)\right\}$

Clearly, total number of elementary events = 36

Let A be the event of getting a pair of aces.

Then A = {(1, 1)}

$\therefore$ n(A) = 1

Hence, required probability = $\frac{n\left(A\right)}{n\left(S\right)}$

$=\frac{1}{36}$