Question

Two dice are thrown simultaneously, the probability of obtaining a total score of $5$ is

• A. $\frac{1}{18}$
• B. $\frac{1}{12}$
• C. $\frac{1}{9}$
• D. $\frac{1}{6}$

Answer 1

Answer: (C)

$\frac{1}{9}$

Let $E$ be the event of getting the sum of $5$.

$E=(1,4),(4,1),(2,3),(3,2)$

So $n\left(E\right)=4$

also $n\left(S\right)=6\times 6=36$

Hence probability of even E is, $P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{4}{36}=\frac{1}{9}$.