Question

Two dice are thrown simultaneously. The probability of selecting a total score 5 is

• A. $\frac{1}{18}$
• B. $\frac{1}{2}$
• C. $\frac{1}{9}$
• D. None of these

Answer 1

Answer: (C)

$\frac{1}{9}$

Total Score will be 5 in following cases
a) 1+4
b) 4+1
c) 2+3
d) 3+2
Therefore there are 4 ways of occurring a total score of 5.
Total ways = 6*6 = 36
Therefore P $=\frac{4}{36}$
i.e. P $=\frac{1}{9}$