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Question

Two dice are thrown. The events A,B and C are as follows:
A : getting an even number on the first die
B : getting an odd number on the first die
C : getting the sum of the numbers on the dice 5
State true or false : (give reason for your answer)
(i) A and B are mutually exclusive
(ii) A and B are mutually exclusive and exhaustive
(iii) A=B
(iv) A and C are mutually exclusive
(v) A and B are mutually exclusive
(vi) A,B,C are mutually exclusive and exhaustive

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Solution

S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)(2,1),(2,2),...........,(2,6)(3,1),(3,2)..............(3,6)(4,1),(4,2).............(4,6),(5,1),(5,2).............(5,6)(6,1),(6,2)...........(6,6)}
A={(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
B={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)}
C={(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)}
(i) Clearly, AB=ϕ
A and B are mutually exclusive.
Thus the given statement is true.
(ii)AB=ϕ and AB=S
A and B are mutually exclusive and exhaustive.
Thus the given statement is true.
(iii)B={(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}=A
Thus the given statement is true.
(iv) AC={(2,1),(2,2),(2,3),(4,1)}ϕ
A and C are not mutually exclusive.
Thus the given statement is false..
(v) AB=AA=A
ABϕ
A and B' are not mutually exclusive.
Thus the given statement is false.
(vi) ABC=S
However BC={(2,1),(2,2),(2,3),(4,1)}ϕ
Therefore events A,B and C are not mutually exclusive and exhaustive.
Thus the given statement is false.

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