Question

Two dice are thrown. The probability of scoring a sum greater than $9$ or a doublet is

• A. $\frac{1}{6}$
• B. $\frac{1}{18}$
• C. $\frac{5}{18}$
• D. $\frac{2}{18}$

Answer 1

Answer: (C)

$\frac{5}{18}$

Scoring a sum greater than $9$ or a doublet is $=(4,6),(6,4),(5,5),(5,6),(6,5),(6,6),(1,1),(2,2),(3,3),(4,4)$
total ways = $10$
The probability of scoring a sum greater than $9$ or a doublet is $=10/36=5/18$