Two dice are thrown together. Teh probability of getting a doublet is
(a) $\frac{1}{3}$ (b) $\frac{1}{6}$ (c) $\frac{1}{4}$ (d) $\frac{2}{3}$

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Solution

Total outcomes = 36
Doublet are 6 (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)

Probability of getting doublet = 6/36
= 1/6

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Q. Two dice are thrown together. The probability of getting a doublet is

(a)

\frac{1}{3}

(b)

\frac{1}{6}

(c)

\frac{1}{4}

(d)

\frac{2}{3}

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6

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Two dice are thrown together. Teh probability of getting a doublet is (a) 13 (b) 16 (c) 14 (d) 23

Total outcomes = 36 Doublet are 6 (1,1),(2,2),(3,3),(4,4),(5,5),(6,6) Probability of getting doublet = 6/36 = 1/6

Two dice are thrown together. Teh probability of getting a doublet is
(a) $\frac{1}{3}$ (b) $\frac{1}{6}$ (c) $\frac{1}{4}$ (d) $\frac{2}{3}$

Total outcomes = 36
Doublet are 6 (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)

Probability of getting doublet = 6/36
= 1/6