Question

Two dice are thrown together, the probability of getting a doublet is ___________.

Answer 1

The outcomes when two dice are thrown together are given below.

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Total number of outcomes = 36

Let E be the event of getting a doublet. The outcomes favourable to event E are (1, 1), (2, 2), (3, 3), (4, 4), (5, 5) and (6, 6).

Favourable number of outcomes = 6

∴ Probability of getting a doublet = $\frac{\mathrm{Favourable}\mathrm{numbers}\mathrm{of}\mathrm{outcomes}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{outcomes}}=\frac{6}{36}=\frac{1}{6}$

Two dice are thrown together, the probability of getting a doublet is $\underline{\frac{1}{6}}$.