Question

Two dice are thrown together. The probability that sum of the two numbers will be 2 is:

• A. $\frac{1}{2}$
• B. $\frac{1}{36}$
• C. $\frac{1}{8}$
• D. $\frac{1}{4}$

Answer 1

The correct option is B $\frac{1}{36}$

Favourable outcome = (1,1)
Total no. of possible outcomes = 36
$\therefore$ P(sum of the numbers will be 2) = $\frac{1}{36}$
Here,{(1,1)} is called elementary event of the sample space.