Question

Two dice are thrown. What is the probability that the sum of the numbers appearing on them is prime?

• A. 5/12
• B. 2/3
• C. 7/12
• D. 11/12

Answer 1

The correct option is A

5/12

Total number of outcomes in the sample space = 36
​Now, favorable outcomes = {(1,1),(1,2),(2,1),(1,4),(2,3),(3,2),(4,1),(1,6),(2,5),(3,4),(4,3),(5,2),(6,1),(6,5),(5,6)}
So, probability =$\frac{15}{36}=\frac{5}{12}$