Two dice are tossed simultaneously. Then the probability that the total score is a prime number is:
5/12
Clearly, (S) = (6 x 6) = 36.
Let E = Event that the sum is a prime number.
Then E = { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3),(5, 2), (5, 6), (6, 1), (6, 5) }
∴ (E) = 15.
So P(E) = 512.