wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two dice each numbered from 1 to 6 are thrown together. Let A and B be two events given by
A: even number on the first die
B: number on the second die is greater than 4

Find the value of P(AB).

A
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
14
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
16
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 16
Given:
Two dice are thrown, hence the total number of all possible ways, n(S)= 6×6=36
A: even number on the first die
B: the number on the second die is greater than 4
To find:
P(AB)
And, AB, means even number on first die and number greater than 4 on second die i.e., {(2,5),(2,6),(4,5),(4,6),(6,5),(6,6)}=6

Hence, P(B)=636=16

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon