Question

Two dice each with faces marked $1,2,3,4,5,6$ are thrown simultaneously. Find the probability of the sum of the numbers coming up is a multiple of $4$.

• A. $\frac{5}{18}$
• B. $\frac{2}{9}$
• C. $\frac{1}{4}$
• D. $\frac{7}{36}$

Answer 1

Answer: (C)

$\frac{1}{4}$

Total possible outcomes$=n\left(S\right)=6\times 6=36$

Favourable outcomes : $(1,3),(2,2),(2,6),(3,1),(3,5),(4,4),(5,3),(6,2),(6,6)$ $\Rightarrow n\left(E\right)=9$

Hence,probability$=\frac{9}{36}=\frac{1}{4}$