Question

Two dice each with faces marked $1,2,3,4,5,6$ are thrown simultaneously. Find the probability of the sum of the numbers coming up $7$.

• A. $\frac{1}{6}$
• B. $\frac{7}{36}$
• C. $\frac{1}{4}$
• D. none of these

Answer 1

The correct option is A $\frac{1}{6}$

Total possible outcomes$=n\left(S\right)$$=6\times 6=36$

Favourable outcomes : $(2,5)(3,4)(6,1)$ repeated twice as number can be on either dice $\Rightarrow n\left(E\right)=6$

Hence,probability$=\frac{6}{36}=\frac{1}{6}$