Question

Two dice, one blue and green are thrown at the same time. What is the probability that the sum of the two numbers appearing on the top of the dice is
$\left(i\right)$ 9
$\left(ii\right)$ Greater than 10
$\left(iii\right)$ Less than or equal to 11

• A. $\left(iii\right)\frac{35}{36}$
• B. $\left(i\right)\frac{1}{9}$
• C. $\left(ii\right)\frac{1}{12}$
• D. $\left(iii\right)\frac{31}{36}$

Answer 1

Answer: (A), (B), (C)

The correct options are
A $\left(iii\right)\frac{35}{36}$
B $\left(i\right)\frac{1}{9}$
C $\left(ii\right)\frac{1}{12}$

Two dice, one blue and green are thrown at the same time in $6\times 6$=36 ways Then n(s)=36
(i)The event of the sum of the two numbers appearing on the top of the dice is 9 are four
Then provability=$\frac{n\left(A\right)}{n\left(S\right)}=\frac{4}{36}=\frac{1}{9}$
(ii)The event of sum of the numbers on two dice is Greater than 10 are Three
Then provability=$\frac{n\left(A\right)}{n\left(S\right)}=\frac{3}{36}=\frac{1}{12}$
(iii)The event of the sum of the two numbers appearing on the top of the dice is Greater than 10 Are 35
Then provability=$\frac{n\left(A\right)}{n\left(S\right)}=\frac{35}{36}$