Two dices are rolled. If both dices have six faces numbered 1,2,3,5,7 and 11, then the probability that the sum of the numbers on the top faces is less than or equal to 8 is:
A
1736
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B
49
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C
512
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D
12
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Solution
The correct option is A1736 n(S)=36
Possible ordered pair : (1,1),(1,2),(1,3),(1,5),(1,7)(2,1),(2,2),(2,3),(2,5),(3,1),(3,2),(3,3),(3,5),(5,1),(5,2),(5,3),(7,1)
Required number of ordered pair =17
Hence, the required probability =1736