Question

Two die are thrown find the probability of getting the sum of the numbers on their upper faces to be at most $3$.

• A. $\frac{1}{4}$
• B. $\frac{1}{6}$
• C. $\frac{1}{12}$
• D. $\frac{1}{36}$

Answer 1

Answer: (C)

$\frac{1}{12}$

Sample space of nos obtained is $=6\times 6$ = $36$ (As two dices are independent)

Sum of nos. obtained atmost $3=(1,1),(1,2)(2,1)=3$
probability of getting the event = $\frac{3}{36}$ =$\frac{1}{12}$