Question

Two die are thrown find the probability of getting the sum of the numbers on their upper faces divisible by 9.

• A. $\frac{1}{9}$
• B. $\frac{2}{9}$
• C. $\frac{1}{3}$
• D. $\frac{4}{9}$

Answer 1

Answer: (A)

$\frac{1}{9}$

Sample space of nos obtained is $=6\times 6$ (As two dices are independent)
Sum of nos. obtained divisible by $9=(3,6),(4,5)(5,4),(6,3)=4$
probability of getting the event = $\frac{4}{36}$= $\frac{1}{9}$