Question

Two die are thrown. Find the probability of the event that the sum of the numbers on their upper faces is $7$:

• A. $\frac{1}{6}$
• B. $\frac{1}{3}$
• C. $\frac{1}{9}$
• D. $\frac{2}{7}$

Answer 1

Answer: (A)

$\frac{1}{6}$

Total number of outcomes $=36$
Favourable outcomes $(6,1),(1,6),(2,5),(5,2),(4,3),(3,4)=6$
Probability $=\frac{6}{36}=\frac{1}{6}$