Question

Two die are thrown. Find the probability that the number on the upper face of the first dice is less than the number on the upper face of the second dice.

• A. $\frac{1}{2}$
• B. $\frac{7}{12}$
• C. $\frac{1}{3}$
• D. $\frac{5}{12}$

Answer 1

Answer: (D)

$\frac{5}{12}$

Sample space of nos obtained is $=6\times 6$ (As two dices are independent)
No. obtained on first dice is less than second $=15$
(if no on first dice is $1$ then possibility on second dice are $5(2-6)$ and similarly for $2=4$ , for $3=3$, for $4=2$ ,for $5=1$ total $5+4+3+2+1=15)$
probability of event $=15/36=5/12$