Two difference gases of molecular masses $M_{1}$ and $M_{2}$ are at the same temperature. What is the ratio of their mean square speeds?

\frac{M_{1}}{M_{2}}

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\frac{M_{2}}{M_{1}}

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\sqrt{\frac{M_{1}}{M_{2}}}

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\sqrt{\frac{M_{2}}{M_{1}}}

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Solution

The correct option is A $\frac{M_{1}}{M_{2}}$
Mean squared speed $= \frac{3 R T}{M}$
$\frac{V_{1}}{V_{2}} = \frac{M_{1}}{M_{2}}$

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Two difference gases of molecular masses M1 and M2 are at the same temperature. What is the ratio of their mean square speeds?

The correct option is A M1M2Mean squared speed =3RTMV1V2=M1M2

Two difference gases of molecular masses $M_{1}$ and $M_{2}$ are at the same temperature. What is the ratio of their mean square speeds?

The correct option is A $\frac{M_{1}}{M_{2}}$
Mean squared speed $= \frac{3 R T}{M}$
$\frac{V_{1}}{V_{2}} = \frac{M_{1}}{M_{2}}$