When two different dice are thrown, then total number of outcomes = 36.
Let E1 be the event of getting the sum of the numbers on the two dice is 10.
These numbers are (4, 6), (5, 5) and (6, 4).
Number of Favourable outcomes = 3
∴ P(getting the sum of the numbers on the two dice is 10) =
=
Thus, the probability of getting the sum of the numbers on the two dice is 10 is .