Question

Two different dice are tossed together. Find the probability of getting a doublet?

Answer 1

Probability of getting a doublet when two different dice are tossed

Total events $n\left(S\right)=6\times 5=36$

Favourable events i.e., to getting doubtets $E=\{(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)\}$

$\therefore n\left(E\right)=6$

Probability of getting a doublets$=\frac{n\left(E\right)}{n\left(s\right)}=\frac{6}{36}=\frac{1}{6}$

$\therefore$Probability of getting a doublets $=\frac{1}{6}$