Question

Two different dice are tossed together. Find the probability of the sum of no's appearing on two dice is $5$.

• A. $\frac{1}{36}$
• B. $\frac{1}{18}$
• C. $\frac{1}{9}$
• D. $\frac{1}{6}$

Answer 1

The correct option is C $\frac{1}{9}$

$\overrightarrow{b}=\left(\sqrt{2}\right)a$

$(6+2a)||\overrightarrow{b}$

$n\left(s\right)=6\times 6$

$n\left(s\right)=36$

$n\left(E\right)=$ sum $=5$

$=(1,4),(2,3),(3,2),(4,1)=4$

$p\left(E\right)=\frac{n\left(E\right)}{n\left(s\right)}=\frac{4}{36}=\frac{1}{9}$.