Sum of observation
=36[(1,1), (1, 2), (1,3), (1,4), (1,5), (1,6), (2,1), (2, 2), (2,3), (2,4), (2,5), (2,6), (3,1), (3, 2), (3,3), (3,4), (3,5), (3,6), (4,1), (4, 2), (4,3), (4,4), (4,5), (4,6), (5,1), (5, 2), (5,3), (5,4), (5,5), (5,6), (6,1), (6, 2), (6,3), (6,4), (6,5), (6,6),]
Favourable observation =3[(4,6)(5,4)(6,4)]
Probability =336=112