Question

Two different digits are chosen at random from the set $1,2,3,4,5,6,7,8.$ Then the probability that their sum will exceed $13$ is

• A. $\frac{5}{14}$
• B. $\frac{3}{14}$
• C. $\frac{1}{14}$
• D. $\frac{2}{14}$

Answer 1

The correct option is C $\frac{1}{14}$

Possible numbers are $(6,8)(7,8)$
$\Rightarrow P=2{/}^8{C}_2=1/14$