Question

Two different digits are chosen at random from the set $1,2,3,4,5,6,7,8.$ Then the probability that both the digits are less than $3$ is

• A. $\frac{3}{28}$
• B. $\frac{1}{14}$
• C. $\frac{1}{28}$
• D. $\frac{7}{28}$

Answer 1

Answer: (C)

$\frac{1}{28}$

Only one such case possible i.e. choosing $1$ and $2$
Therefore, $P=1{/}^8{C}_2=1/28$