Question

Two different liquids of same mass are kept in two identical vessels, which are placed in a freezer that extracts heat from them at the same rate causing each liquid to transform into a solid. The schematic figure shows the temperature T vs time t plot for the two material. We denote the specific heat of materials in the liquid(solid) states to be $C_{L1}\left(C_{S1}\right)$ and $C_{L2}\left(C_{S2}\right)$ respectively. Choose the correct option.

• A. $C_{L1}<C_{L2}$ and $C_{S1}<C_{S2}$
• B. $C_{L1}>C_{L2}$ and $C_{S1}<C_{S2}$
• C. $C_{L1}>C_{L2}$ and $C_{S1}>C_{S2}$
• D. $C_{L1}<C_{L2}$ and $C_{S1}>C_{S2}$

Answer 1

The correct option is B $C_{L1}>C_{L2}$ and $C_{S1}<C_{S2}$

Clearly, initial slopes show the temperature change in the solid state. As in 1st curve, there is a large change in temperature in the same time interval compared to that of 2nd curve i.e slope of 1 is larger so $c_{S1}<c_{S2}$.

Similarly, slope of curve 2 is larger in the later part of the graph hence, $c_{L1}<c_{L2}$