The correct option is C 22/3:1
Let us suppose the surface tension is T, the radius of smaller drop is r and that of bigger drop is R.
As total volume of fluid will be same
∴ Volume of two smaller drops = Volume of bigger drop
⇒2×43πr3=43πR3
⇒R=21/3r ......(1)
Now, ratio of surface energies
EbigEsmall=T×4πR2T×4πr2
[ surface energy =surface tension × surface area ]
=R2r2=22/3:1 [ from (1) ]