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Question

Two drops of phenolphthalein solution was added to 40.0mL of an HCl solution. This solution was titrated with 0.10M NaOH solution. When 30.0mL of base had been added, part of the solution turned pink; but the colour disappeared upon mixing the solution. Addition of NaOH solution was continued dropwise until one drop addition produced a lasting pink colour. At this point, the volume of base added was 32.56mL. Calculate:
(i) The concentration of HCl solutions
(ii) Concentration of HCl in solution when 30.0mL base had been added.

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Solution

40 ml of HCl needed 32.56 ml of NaOH 0.10 M
M1V1=M2V2
40×M1=0.1×32.56
M1=0.1×32.5640=0.0814
conc. of HCl when 30ml base added :
M1V1M2V2V1+V20.0814×4030×0.170
2.56×0.1700.0037M

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