Two drops of small radius are falling in air with constant velocity 5cms−1. If they coalesce, then the terminal velocity will be
A
10cms−1
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B
2.5cms−1
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C
5×3√4cms−1
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D
5.√2cms−1
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Solution
The correct option is C5×3√4cms−1 Let the radius of smaller drops =r r3=V radius of larger coslesce drop= 21/3r V of smaller drops ==2g(T−s)r29η=5 ----------(1) V of larger drops= =2g(T−s)r29η22/3[from(1)] =5×22/3cm/s =5×3√4cm/s