Two electric bulbs have tungsten filament of same length. If one of them gives 60 W and the other 100 W, then

100 W bulb has thicker filament

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

60 W bulb has thicker filament

No worries! We‘ve got your back. Try BYJU‘S free classes today!

both filaments are of same thickness

No worries! We‘ve got your back. Try BYJU‘S free classes today!

It is not possible to get different wattages unless the lengths are different

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 100 W bulb has thicker filament
We know that, $P = \frac{V^{2}}{R}$ for same mains circuit $V$ is same.
Thus, $R_{60} > R_{100}$
Also, $R = \frac{ρ L}{A}$ where $ρ =$ resistivity, $A =$ area and $L =$ length of wire.
Thus less resistor implies more thicker element.
So the $100 W$ bulb has thicker filament.

Suggest Corrections

Similar questions

Q. Two electrical bulbs have tungsten filament of same length. If one of them gives 60 watts and other 100 watts, then

Q. Two bulbs of equal wattage, one having carbon filament and the other having a tungsten filament, are connected in series to the mains. Then

Q. A 100 W bulb has tungsten filament of total length 1.0 m and radius 4 × 10⁻⁵ m. The emissivity of the filament is 0.8 and σ = 6.0 × 10⁻⁸ W m⁻²K⁴. Calculate the temperature of the filament when the bulb is operating at correct wattage.

Q. A

100 - W

bulb and a

25 - W

bulb are designed for the same voltage. They have filaments of the same length and material. The ratio of the diameter of the

100 - W

bulb to that of the

25 - W

bulb is

Two light bulbs P and Q are identical in all aspects, except that P's filament is thicker than Q's. If the same potential difference is applied to each, then:

Join BYJU'S Learning Program

Two electric bulbs have tungsten filament of same length. If one of them gives 60 W and the other 100 W, then

The correct option is A 100 W bulb has thicker filamentWe know that, P=V2R for same mains circuit V is same.Thus, R60>R100Also, R=ρLA where ρ= resistivity, A=area and L= length of wire.Thus less resistor implies more thicker element.So the 100 W bulb has thicker filament.