Resistances of both the bulbs are
R1=V2P1=220225
R2 =V2P2=2202100
henceR1:R2
When connected in series, the voltages divide in them in the ratio of their resistances. The voltage of 440 V devides in such a way that voltage across 25 w bulb will be more than 220 V. Hence 25 w bulb will fuse.