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Question

Two electric charges 12 μC and 6 μC are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from 6 μC charge is

A
0.10 m
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B
0.15 m
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C
0.20 m
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D
0.25 m
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Solution

The correct option is C 0.20 m
Point P will lie near the charge which is smaller in magnitude i.e. 6 μC. Hence potential at P

V=14πϵ0(6×106)x+14πϵ0(12×106)(0.2+x)=0x=0.2 m

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